Question

the magnetic flux linked with a coil is given by the equation- 8t^2+ 3t+5 . induced emf in coil at FOURTH second will be

Answer 1

induced emf ξ = - $\frac{d \Phi}{dt},\ where\ \Phi=total\ magnetic\ Flux\ through\ the\ coil.$

ξ = - d (8 t² + 3 t + 5) / d t
   = - 16 t + 3
   = -16 * 4 + 3 = - 61 Volts.

Answer 2

Answer:

16

Explanation:

flux = 8t 2 +3t + 5

E = d(flux)/d(t)

= d(8t2+3t+5)/dt

=16t+3

flux at 4th second = flux at t=4 — flux at the t= 3

= 16(4)+3 —16(3)+3

= 16