The magnetic flux passing through a coil changes from 6 x10-³ wb to 7.2x10⁻³ wb in 0.02 second. Calculate the magnitude of e.m.f. induced.
Answers
Answered by
5
initial magnetic flux = 6 × 10^-3 wb
final magnetic flux = 7.2 × 10^-3 wb
time taken to change the flux = 0.02 second
we know, induced emf = negative of rate of change of magnetic flux
= -(final magnetic flux - initial magnetic flux)/time
= -(7.2 × 10^-3 - 6 × 10^-3)/0.02
= -1.2 × 10^-3/2 × 10^-2
= - 0.6 × 10^-1 V
= -0.06 V
hence, magnetic of induced emf = 0.06V
final magnetic flux = 7.2 × 10^-3 wb
time taken to change the flux = 0.02 second
we know, induced emf = negative of rate of change of magnetic flux
= -(final magnetic flux - initial magnetic flux)/time
= -(7.2 × 10^-3 - 6 × 10^-3)/0.02
= -1.2 × 10^-3/2 × 10^-2
= - 0.6 × 10^-1 V
= -0.06 V
hence, magnetic of induced emf = 0.06V
Similar questions