Question

A magnetic flux of 5 microweber is linked with a coil when a current of ImA flows through it. What is the self inductance of the coil ?

Answer 1

given :

Ф= Li

L=Ф/I

Ф= 5 micro weber= 5x10⁻⁶ w

i=mA=10 ⁻³ A

L= 5x 10⁻⁶/10⁻³

L= 5x 10⁻³ wb/A

∴self inductance of the coil  is 5x 10⁻³ wb/A