Question

The magnetic flux through a coil having 100 turns decreases from 5milli weber to 0 in 5 second. Calculate the e. m. f induced in the coil

Answer 1

Answer:The induced e.m.f in the coil is 0.1 V.

Explanation:

Given that,

Number of turns N = 100

Time t = 5 sec

Magnetic field $B = 5\ milli\ weber$

We know that,

The induced e.m.f is the product of number of turns and change in magnetic flux per unit time.

$\epsilon= \dfrac{N\times d\phi}{dt}$

$\epsilon= \dfrac{100\times5}{5}$

$\epsilon = 0.1 V$

Hence, The induced e.m.f in the coil is 0.1 V.

Answer 2

Answer:

Decrease in the flux = 0.005 - 0 = 0.005

Weber,

no of turns = 100 turns

time = 5 s

e.m.f induced = n × rate of increase of magnetic flux

= 100 ×× 0.005 / 5

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• • e.m.f induced e = 0.1 v = 100 mv