Question

The magnetic flux through a coil perpendicular to the plane is varying according the relation phi = (5t^3 + 4t^2 + 2t - 4) Wb. Calculate the induced current through the coil at t = 2 seconds,if the resistance of the coil is 5 ohms

Answer 1

hey mate
here's the solution

Answer 2

Explanation:

It is given that,

The magnetic flux through a coil perpendicular to the plane is varying according the relation as :

$\phi=(5t^3+4t^2+2t-4)\ Wb$

Induced EMF is given by :

$E=\dfrac{d\phi}{dt}$

$E=\dfrac{d(5t^3+4t^2+2t-4)}{dt}$

$E=15t^2+8t+2$

induced emf at t = 2 seconds will be :

$E=15(2)^2+8(2)+2=78\ V$

From Ohm's law as :

$E=IR$

I is the induced current

$I=\dfrac{E}{R}$

$I=\dfrac{78}{5}=15.6\ A$

So, the induced current through the coil at t = 2 seconds is 15.6 A. Hence, this is the required solution.