Question

the magnetic force acting on a charged particle having charge 1 micro centrimeter moving with velocity ( i + 2j) * 10^8 m/s in a uniform mahnetic field of (2j) T is

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Answer 1

answer : 10 N/C

explanation : charge on particle,

q = 10µC = 10 x 10^-6C = 10^-5 C

mass of particle

= m = lug

= 10^-9 kg

magnetic field , B = 0.1T

so, magnetic force acting on particle,

F = q\v X B)

= qvBsino

= 10^-5 x V x 0.17 x sin 90°

= 10^-6 x V .......(1)

radius of circle,

r = mv/qB

so, v = qBr/m .....(2)

from equations (1) and (2),

F = 10^-6 x {10^-5 C x 0.1T x 0.1m/10^-9kg}

= 10^-4 N

now, force due to electric field,

F = qE =

so, 10^-4 = 10^-5 x E

or, E = 10 N/C

hence, electric field = 10 N/C