Physics, asked by MelodiQ, 4 months ago

The magnetic force on a long charge is F=q(v×B). Here q= electric charge,v=velocity of point charge,B=magnetic field.The dimensions of B are 

a. [MLT^-1A]
b. [M²LT^-2A^-1]
c. [MT^-2A^-1]
d. none of these​

Answers

Answered by chjaswitha
0

Answer:

MT^-2A^-1

Explanation:

F=q(v×B)

F=qvb sin theta.q

dimension of q=[AT]

". of v=[LT^-2]

". of F =[MLT^-2]

the answer is continued in the above attached paper please check it

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