The magnetic force on a long charge is F=q(v×B). Here q= electric charge,v=velocity of point charge,B=magnetic field.The dimensions of B are
a. [MLT^-1A]
b. [M²LT^-2A^-1]
c. [MT^-2A^-1]
d. none of these
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Answer:
MT^-2A^-1
Explanation:
F=q(v×B)
F=qvb sin theta.q
dimension of q=[AT]
". of v=[LT^-2]
". of F =[MLT^-2]
the answer is continued in the above attached paper please check it
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