Question

The magnetic induction at the centre of a long solenoid, having 5000 turns per metre is 3.142 10 T. Find the current in the solenoid.​

Answer 1

Explanation:

B =μ0nI∴ The current in the solenoid,

$I - \frac{B}{μ0nI} - \frac{3.142 \times {10 }^{ - 3} }{4 \times 3.142 \times {10}^{7} \times 500 } - \frac{10}{20} = 0.5A$

$\huge \pink{~} \red {τ} \green {α} \blue {v} \orange {v} \pink {u} \red {♡}$