Question

The magnetic moment of K3[Fe(CN)6] is found to be 1.7 BM. How many unpaired electron (s) is/are present per molecule?

Answer 1

Final Answer : 1

Steps:
1) The spin only magnetic moment is given by
√n(n+2) .
Since,
Spin only magnetic moment is given by 1.7BM
=> √n(n+2) = 1.7
=> n = 1 since n is whole number.
=> CN-is strong field Ligand.
=> This is Low spin complex.

Answer 2

the right answer is 1....