The magnetic moment of short bar magnet is 2. The magnetic field at a point 1m away from it in a firection making an angle of 50 with magnetic moment is
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B = μ/4pi * M/r^3 * Sqrt (1+ 3* cos^2 θ).
μ=10^-7 units
M=Magnetic moment = 2 units
r =1m. θ= 50 deg.
So B = 2.25* 10^-7 Tesla
Angle of the magnetic field B with the moment M = θ + Tan^-1 ((tanθ)/2) = 80.78 deg
μ=10^-7 units
M=Magnetic moment = 2 units
r =1m. θ= 50 deg.
So B = 2.25* 10^-7 Tesla
Angle of the magnetic field B with the moment M = θ + Tan^-1 ((tanθ)/2) = 80.78 deg
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