the magnification of an image formed by a lens is -1. if the distance of the image from optic centre of the lens is 25cm, where is the object placed? find the nature and focal length of the lens.
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Answer:
The object is placed at the center of curvature.
Concave lens
Image is real inverted and of the same size
Explanation:
m= -( v/u)
Therefore=> - 1= - 25/u => u = 25
Focal length =uv/(u-v)
=25*25/(25+25)
=25*25 /50
=12.5 cm ans
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