The magnification of the image formed by a lens is +1 for the object position at 32cm in front of the lens. Then the power of a lens will be
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The magnification of the image formed by a lens is +1 for the object position at 32 cm in front of the lens.
To find : The power of lens will be....
solution : using formula,
magnification of lens, m = v/u
here object distance, u = -32 cm
⇒+1 = v/-32 cm
⇒v = -32 cm
now find focal length of lens.
using formula, 1/v - 1/u = 1/f
⇒1/-32 - 1/-32 = 1/f
⇒1/-32 + 1/32 = 1/f
⇒0 = 1/f
as you know power of lens, p = 1/f
so, P = 1/f = 0
Therefore the power of lens will be zero.
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