Physics, asked by adi20043005, 7 months ago

The magnitude and direction of 2i+4j are 1.)sqrt(2),tan45 2.)sqrt(20), tanA = 2 3.)sqrt (20) , tanA = 1/2 4.)1, tanA =2

Answers

Answered by ramtajogi3113
0

Answer:

i don't no

good night everyone

Answered by BearKnight
0

Answer:

Let the given vector be

a

=2

i

^

+3

j

^

To find the component of 'a' along

i

^

+

j

^

we have to find unit vector along

i

^

+

j

^

Let the unit vector be

a

^

a

^

=

i

^

+

j

^

i

^

+

j

^

=

2

1

(

i

^

+

j

^

)

Component of

a

along

i

^

+

j

^

=(

a

a

^

)

a

^

=[(2

i

^

+3

j

^

)⋅

2

1

(

i

^

+

j

^

)]

2

1

(

i

^

+

j

^

)

=[

2

1

(2+3)]

2

1

(

i

^

+

j

^

)

=

2

5

[

2

1

(

i

^

+

j

^

)]

=

2

5

i

^

+

2

5

j

^

Component of

a

along

i

^

j

^

=(

a

a

^

)

a

^

=[(2

i

^

+3

j

^

)⋅

2

1

(

i

^

j

^

)]

2

1

(

i

^

j

^

)

=[

2

1

(2−3)]

2

1

(

i

^

j

^

)

=

2

−1

[

2

1

(

i

^

j

^

)]

=−

2

1

i

^

+

2

1

j

^

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