Question

The magnitude of change in velocity of a particle
having speed v is v during a time interval ∆t while
moving in a uniform circular motion. The magnitude
of average force on the particle is proportional to
(1)v/(2∆t)
(2)v/∆t
(3)(Πv)/(3∆t)
(4)(Πv)/(2∆t)​

Answer 1

Explanation:

Here is your solution

Let the radius of the circle be

Let the radius of the circle be R

Let the radius of the circle be R

Since the particle hasn't changed its velocity,

Since the particle hasn't changed its velocity, v

Since the particle hasn't changed its velocity, v1

Since the particle hasn't changed its velocity, v1=

Since the particle hasn't changed its velocity, v1=v

Since the particle hasn't changed its velocity, v1=v2

Since the particle hasn't changed its velocity, v1=v2

Since the particle hasn't changed its velocity, v1=v2 Solving the above expression we ges,

s,average Velocity