Physics, asked by suman6122, 1 year ago

The magnitude of change in velocity of a particle
having speed v is v during a time interval At while
moving in a uniform circular motion. The magnitude
of average force on the particle is proportional to​

Answers

Answered by 124568900
0

Answer:

Explanation:

Pi×v/3t

Answered by jitushashi143
0

The magnitude  of average force on the particle is proportional to​ the centripetal acceleration, a = v²/r

Explanation:

  1. If the velocity of the particle is v, then the speed of the particle is v
  2. The velocity is a vector having magnitude and direction.
  3. The magnitude of the velocity components in the coordinate axes is equal to the speed.
  4. The speed is a scalar quantity having only the magnitude.
  5. So, if a particle is in uniform circular, it has a uniform centripetal speed. But, its velocity changes in time.
  6. Since there is a change in velocity at each instant of time. It is in accelerated motion.
  7. Hence, the force acting on the body is proportional t the centripetal acceleration, a = v²/r
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