Physics, asked by pallavibhople3666, 10 months ago

the magnitude of scalar product of two unit vectors making an angle of 60 degree with each other is​

Answers

Answered by azizalasha
0

Answer:

1/2

Explanation:

magnitude = cos60 = 1/2

Answered by sadiaanam
0

Answer:

The magnitude of scalar product of two unit vectors making an angle of 60 degree with each other is​ 1/2 .

Explanation:

The scalar product is also termed as the dot product or inner product and remember that scalar multiplication is always denoted by a dot.

Where:

  • ∣a∣ is the magnitude (length) of vector a
  • ∣b∣ is the magnitude (length) of vector b
  • θ is the angle between a and b

So, we multiply the length of a times the length of b .

then multiply by the cosine of angle between a and b .

Since ∣ a ∣,∣ b ∣ and cosθ are scalars, so the dot product of  a  and  b  is a scalar quantity.

That is why dot product of two vectors is also called scalar product. Each vector  a  and  b  has a direction, but their scalar product does not have a direction.

To multiply two vectors it makes sense to multiply their length together but only when they point in the same direction.

So we make one, "point in the same direction"as the other by multiplying by cosθ. Scalar product of two vectors in term of their components:

a . b =∣ a ∣∣ b ∣cosθ =abcosθ

Therefore, cos60 =1/2

So , The magnitude of scalar product of two unit vectors making an angle of 60 degree with each other is​ 1/2 .

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