Physics, asked by Anuskarawat60451, 10 months ago

The magnitude of the de-Broglie wavelength (????) of electron
(e), proton (p), neutron (n) and α-particle (α) all having the
same energy of 1 MeV, in the increasing order will follow the
sequence
(a) ????ₑ, ????ₚ, ????ₙ, ????ₐ (b) ????ₑ, ????ₙ, ????ₚ, ????ₐ
(c) ????ₐ, ????ₙ, ????ₚ, ????ₑ (d) ????ₚ, ????ₑ, ????ₐ, ????ₙ

Answers

Answered by rahulgupta86
0

Answer:

Answer is PORTON is a right answer

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