Question

The orbital speed of electron orbiting around a nucleus in a
circular orbit of radius 50 pm is 2.2 × 10⁶ ms⁻¹. Then the
magnetic dipole moment of an electron is
(a) 1.6 × 10⁻¹⁹ Am² (b) 5.3 × 10⁻²¹ Am²
(c) 8.8 × 10⁻²⁴ Am² (d) 8.8 × 10⁻²⁶ Am²

Answer 1

Magnetic dipole moment

m=iA=

T

e

×πr

2

=

(2πr/v)

e

×πr

2

=

2

erv

=

2

1.6×10

−19

×50×10

−12

×2.2×10

6

=8.8×10^ −24Am2