Physics, asked by alokkiran9482, 1 year ago

The magnitude of the de-Broglie wavelength (λ) of electron (e), proton (p), neutron (n) and α-particle (α) all having the same energy of 1 MeV, in the increasing order will follow the sequence
(a) \lambda_{e},\lambda_{p},\lambda_{n},\lambda_{\alpha}
(b) \lambda_{e},\lambda_{n},\lambda_{p},\lambda_{\alpha}
(c) \lambda_{\alpha},\lambda_{n},\lambda_{p},\lambda_{e}
(d) \lambda_{p},\lambda_{e},\lambda_{\alpha},\lambda_{n}

Answers

Answered by ROCKSTARgirl
0

[B] is the correct option

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