Physics, asked by smithvanessa1870, 1 year ago

Two radiations of photons energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds ofthe emitted electrons is(a) 1 : 4(b) 1 : 2(c) 1 : 1(d) 1 : 5

Answers

Answered by Anonymous
1

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Option : 1)

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Two radiations of photons energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds ofthe emitted electrons is(a) 1 : 4

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Answered by Anonymous
8

Answer:

B) 1:2

Explanation:

First energy = 1eV (Given)

Second energy = 2.5eV (Given)

Photosensitive metallic surface of work function = 0.5 eV (Given)

1/2mv² = hc/λ - ∅

Case 1 = 1/2mv² = 1 - 0.5 = 0.5ev --- eq 1

Case 2 = 1/2mv² = 2/5 - 0.5 = 2ev --- eq 2

Thus, dividing 1 and 2

V1²/V2² = 1/4 or

V1/V2 = 1/2

Thus, the ratio of the maximum speeds ofthe emitted electrons is 1:2.

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