Physics, asked by Trupti1517, 4 months ago

The magnitude of the displacement vector from a point (0,3,-1) to the point (-2,6,4) in meters will be...??????​

Answers

Answered by celljovi007
0

Explanation:

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Answered by kmousmi293
0

Answer:

The magnitude of the displacement vector will be \sqrt{38} units.

Explanation:

Given Data:
The given two points are

The coordinates of the Initial Point are (0, 3, -1)

The coordinates of the final point are (-2, 6, 4)

To Find :

The magnitude of displacement between the initial and final point.

Calculations:

The coordinates of the initial and final points are (0,3,-1) and (-2,6,4) respectively.

Displacement is the shortest distance between the final and initial points.

Displacement is a vector quantity that possesses both, direction and magnitude.

So, For calculating the displacement, we employ the distance formula,

Thus, Displacement (D) is given byD =\sqrt{(0+2)^{2} +(3-6)^{2} +(-1-4)^{2} } = \sqrt{2^{2} +(-3)^{2} +(-5)^{2} } =\sqrt{38}

Thus, the displacement will be \sqrt{38} units.

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