The magnitude of the force involved in a certain collision (measured in newtons) is equal to the change in momentum (measured in kilogram meters/second). What is the time interval of the collision?
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Let the mass of the body is m and moving with an acceleration a
It's momentum, if it's initial velocity is u and final velocity is v, is = m(v-u)
According to question
F=∆p
ma=m(v–u)
let this be equation 1
But actually F = ∆p/t
ma = m(v-u)/t
t = m(v-u)/ma = 1 as m(v-u) = ma
So t = 1sec
HOPE IT HELPS...... :-)
It's momentum, if it's initial velocity is u and final velocity is v, is = m(v-u)
According to question
F=∆p
ma=m(v–u)
let this be equation 1
But actually F = ∆p/t
ma = m(v-u)/t
t = m(v-u)/ma = 1 as m(v-u) = ma
So t = 1sec
HOPE IT HELPS...... :-)
Answered by
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force is impulse x time
force =impulse. given
force/impulse is time
so time is equal to one sec
force =impulse. given
force/impulse is time
so time is equal to one sec
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