Question

The magnitudes of the resultant of two concurrent forces including an angle of 900 between them is √13 KN. When this included angle is changed to 600, the magnitude of the resultant is √19KN.Interpret the magnitude of the two forces.​

Answer 1

Answer:

Let the forces be F1 and F2

F1^2 + F2^2 = 10

as the angle between them is 90 degrees

when angle is 60

F1^2 + F2^2 + 2 * F1 * F2 *cos(60)=13

10 + F1 * F2=13

3 = F1 * F2

(F1 + F2)^2 = F1^2 + F2^2 + 2 * F1 * F2 = 10 + 6 = 16

F1 + F2 = 4

F1 - F2 = √( ( F1 + F2)^2 - 4F1 * F2) = 2

from eq.(1) and (2) We get

F1 = 3N ,and F2 = 1

Answer 2

Answer:

SORRY for the error but I am not sure