Question

the magnitudr of two vector is 8and that of vector product is 8root 3the angle between them is

Answer 1

a.b = |a||b|cosTheta = 8
a*b = |a||b|sin theta = 8 root 3
Sin theta/cos theta = Tan theta
tan theta = root 3
theta = 60 degrees

Answer 2

A=B=8
√(A²+B²+2ABcos∅)
8√3=√(8²+8²+2*8²cos∅)
3=2+2cos∅
∅=60°