Math, asked by santoshkumardaksh, 1 month ago

The man is 3 times as old as his son . After 15 years, he will be only twice as old as his son . Find the present ages.​

Answers

Answered by Anonymous
3

Answer:

15 & 45 years

Step-by-step explanation:

Given: The man is 3 times as old as his son.

Let the present age of son be x.

The present age of the man = 3x

Again,

After 15 years,

The age of the son = x+15

The age of the man = 3x+15

A/Q,

2×( The age of son) = The age of man

=> 2(x+15) = 3x+15

=> 2x+30 = 3x+15

=> 3x-2x = 30-15

x = 15 years.

Therefore, The present age of son = 15 years

The present age of man = 3x = 3× 15 = 45 years.

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