The man is 3 times as old as his son . After 15 years, he will be only twice as old as his son . Find the present ages.
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Answer:
15 & 45 years
Step-by-step explanation:
Given: The man is 3 times as old as his son.
Let the present age of son be x.
The present age of the man = 3x
Again,
After 15 years,
The age of the son = x+15
The age of the man = 3x+15
A/Q,
2×( The age of son) = The age of man
=> 2(x+15) = 3x+15
=> 2x+30 = 3x+15
=> 3x-2x = 30-15
x = 15 years.
Therefore, The present age of son = 15 years
The present age of man = 3x = 3× 15 = 45 years.
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