the man swims across the river with speed of five kilometer per hour in still water while the boat goes up stream with speed twelve kilometre per hour in in still water how fast and in which direction does the man appear her to go to the boatmen? given that in the speed of flowing water is two kilometers per hour
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The man swims perpendicular to the flow or velocity of river water.
speed of man = 5 kmph wrt water
boat is going upstream , velocity wrt water = 12 kmph
velocity of water in the river = 2 kmph
The vector component of velocity of water downstream is added to both boatman and the swimmer. When we find the relative velocity of the swimmer wrt boatman, that will be canceled.
relative velocity of swimmer wrt boatman
= velocity of swimmer - velocity of boatman (vector subtraction)
as angle between the two vectors is 90 deg,
magnitude of relative velocity = √(5² + 12²) = 13 kmph
direction: at an angle of tan⁻¹ (12/5) to the flow of water
hope it helps u
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