Question

the market price of a water cooler is rupees 5,400. the shopkeeper offers an off season discount of 20 percent on it. Find its selling price

Answer 1

Solution:-

》given:-

》market price of a water cooler = 5400 rupees

》discount = 20%

》then :-

》20% of 5400

》5400×1/5 = 1080rupees

》selling price = 5400-1080

= (4320rupees) ans
》

Answer 2

$\bf{Given}$:
Marked Price (M.P) of the water cooler is ₹ 5400
Discount % = 20%

$\mathbb{\underline {TO \: \: BE \: \: FOUND}}$:
Selling Price (S.P) of the water cooler.

$\bf{\underline{SOLUTION}}$ :

$Discount = \frac{M.P \times Discount\%}{100} \\ \\ Discount = \frac{5400 \times 20}{100} = 1080$

$\therefore$ Discount is ₹ 1080

Now,

Selling Price (S.P) = M.P - Discount

S.P = 5400 - 1080

S.P = ₹ 4320

Hence, S.P of the water cooler is ₹ 4320.