Math, asked by gouthamsn123, 9 months ago

The marketed price of a watch was 820 rs. A man bought the same for 570.72 after getting two successive discounts of which the first was 20%. The rate of second discount was


Answers

Answered by varunvbhat26
1

Answer: 13%

Step-by-step explanation:

Marked Price (Marketed Price) = ₹820

Rate of first discount = 20%

First Discount (in ₹) = 20% of ₹820 = ₹164

Price after first discount = ₹820 - ₹164 = ₹656

Let the rate of second discount be = x %

This discount will be on the price obtained after the first discount, i.e., ₹656.

Second Discount = x % of ₹656

We know that the man bought the watch for ₹570.72 which is the price obtained after the second discount.

Marked Price / Price after first discount =  ₹656

Selling price / Price after second discount = ₹570.72

Second Discount (in ₹) = ₹656 - ₹570.72 = ₹85.28

Therefore, x % of ₹656 = ₹85.28

x % of ₹656 = ₹85.28

(x/100) × 656 = ₹85.28

x × 656 = 85.28 × 100

x × 656 = 8528

x = 8528/656

x = 13

Therefore, the rate of second discount is 13%.

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