The marks in some post degree examination are Normally distributed mean= 500 and deviation = 100 we have to pass 550 students out of 674 students who are appearing in the examination. what should be the minimum marks for passing the examination
Answers
Answer:
The mean mark of 500 students is normally distributed with 55 & standard deviation is 12. Find the no. of students securing marks above 60 & below 45?
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ok so here, n=500
X1=45 and X2=60
mean m=55
std deviation s=12
for normal distribution, we need to convert X1 and X2 to Z1 and Z2
Z1=(X1-m)/s Z2=(X2-m)/s
on substituting values we get Z1=-0.83 and Z2=1.25
Now we see values of areas A1(-0.83) and A2(1.25), corresponding to Z1 and Z2 from cumulative normal distribution table.
A1=1-0.7967=0.2023 (Since Z1 is Negative)
A2=0.8944
Therefore, number of students below 45=0.2023X500=101 (on rounding off)
Number of students above 60=(1-0.8944)X500=53 (on rounding)
How many students scored between 30 and 60 given the mean of 65 and standard deviation of 10 where total number of students is 1280?
The mean and standard deviation of the marks obtained by 1000 students in an examination are respectively 34.5 and 16.5. Assuming the normality of the distribution. What’s the approximate number of students excepted to obtain marks between 30 and 60?
Scores are normally distributed with a mean of 86 and a standard deviation of 14. What is the probability that a random student scored below 72?
In a class of 180 students, statistics grades are normally distributed with a mean of 75 and a standard deviation of 10. What percentage of students got lower than 90? What percentage of students got above a 70?
The marks of 500 candidates in an examination are normally distributed with a mean of 45 and standard deviation of 20 marked. If 400 candidates to be passed, what should be the lowest marks for passing?
Given that,
N = 500, X (Mean) = 55, S (Sigma) = 12 and Marks are normally distributed
To find out,
Number of students scoring marks above 60 and below 45.
Let X1 = 45 and X2 = 60
First calculate the Z value for each by the following formula:
Z1 = (X1 - X)/S
and
Z2 = (X2-X)/S
Substitute the given values in the above equation and you will get the Z1 and Z2 values. Look for Z-table and find the corresponding values against Z1 and Z2.
(Note: If any of the value of Z1 and Z2 is negative, then subtract the subsequent Z-table value from 1)
The obtained values are the percentage of students. Multiply the percent
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How many students scored between 30 and 60 given the mean of 65 and standard deviation of 10 where total number of students is 1280?
The mean and standard deviation of the marks obtained by 1000 students in an examination are respectively 34.5 and 16.5. Assuming the normality of the distribution. What’s the approximate number of students excepted to obtain marks between 30 and 60?
Scores are normally distributed with a mean of 86 and a standard deviation of 14. What is the probability that a random student scored below 72?
In a class of 180 students, statistics grades are normally distributed with a mean of 75 and a standard deviation of 10. What percentage of students got lower than 90? What percentage of students got above a 70?
The marks of 500 candidates in an examination are normally distributed with a mean of 45 and standard deviation of 20 marked. If 400 candidates to be passed, what should be the
Answer:
yes upper answer is right