Question

The marks obtained by 116 students were grouped in a frequency table in class-intervals of 10 marks each,and the median of this distribution was found to be 35.5 on subsequent verification, it was found that two observations belonging to the class-interval(31-40) were included in the class-interval(21-30) by mistake. After correction of this error, the median was found to be 36.5 Calculate the correct frequency in the class-interval(31-40)​

Answer 1

Answer:

Let (21-30) and (31-40) denote the kth and (k + 1)th class intervals respectively. Then, if before correction fk and fk+1, are frequencies of those intervals then after correction (2 observations are shifted from (31 - 40) to (21-30)), frequency of kth interval becomes fk+2 and frequency of (k + 1)th interval becomes fk+1 - 2 Read more on Sarthaks.com - https://www.sarthaks.com/288263/the-marks-obtained-students-are-grouped-in-frequency-table-in-class-intervals-marks-each

Step-by-step explanation:

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