The marks (out of 15) obtained by 20 students in a
science test are listed below:
7, 10, 13, 4, 2, 8, 9, 12, 7, 2, 0, 3, 1, 15, 6, 5, 14, 11, 8, 15
The median
Answers
Step-by-step explanation:
Length of a rectangle is 5 m less than four times its width/breadth .
Perimeter of Rectangle is 180 m .
To Find :
Area of Rectangle .
Solution :
⟼LetWidthbe=x\longmapsto\tt{Let\:Width\:be=x}⟼LetWidthbe=x
As Given that Length of a rectangle is 5 m less than four times its width/breadth . So ,
⟼LengthofRectangle=4x−5\longmapsto\tt{Length\:of\:Rectangle=4x-5}⟼LengthofRectangle=4x−5
Using Formula :
⟼PerimeterofRectangle=2(l+w)\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+w)}⟼
PerimeterofRectangle=2(l+w)
Putting Values :
⟼180=2(4x−5+x)\longmapsto\tt{180=2(4x-5+x)}⟼180=2(4x−5+x)
⟼1802=5x−5\longmapsto\tt{\cancel\dfrac{180}{2}=5x-5}⟼
2
180
=5x−5
⟼90+5=5x\longmapsto\tt{90+5=5x}⟼90+5=5x
⟼955=x\longmapsto\tt{\cancel\dfrac{95}{5}=x}⟼
5
95
=x
⟼19=x\longmapsto\tt\bf{19=x}⟼19=x
So , The value of x is 19 .
Therefore :
⟼Length=4(19)−5\longmapsto\tt{Length=4(19)-5}⟼Length=4(19)−5
⟼71m\longmapsto\tt\bf{71\:m}⟼71m
⟼Width=71m\longmapsto\tt\bf{Width=71\:m}⟼Width=71m
For Area of Rectangle :
Using Formula :
⟼AreaofRectangle=l×w\longmapsto\tt\boxed{Area\:of\:Rectangle=l\times{w}}⟼
AreaofRectangle=l×w
Putting Values :
⟼71×19\longmapsto\tt{71\times{19}}⟼71×19
⟼1349m2\longmapsto\tt\bf{1349\:{m}^{2}}⟼1349m
2
So, The Area of Rectangle is 1349 m² .
0, 15, 10, 5, 16, 25, 20, 24, 12, 20
Let's arrange the data in ascending order.
5, 9, 10, 12, 15, 16, 19, 20, 20, 20, 20, 23, 24, 25, 25
Mode - Since 20try by yourself
The most certain way to succeed is always to try just one more time. . Motivational Time Always. The only failure is not to try
here is my help
Given data,
19, 25, 23, 20, 9, 2 occurred the maximum number of times, it becomes the mode of our data.
2
n + 1
)
th
term = =\ \frac{15+1}{2}\ =\ \frac{16}{2}\ =\ 8=
2
15+1
=
2
16
= 8
8th term = 20
Therefore, Mean = Median ( 20 = 20 )