The marks scored by 40 students in a test are distinct and have integral values. If the highest score is 120 and their average score is 100.5, then find the average of the least and the second least mark.
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i can't understand but I think this
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Step-by-step explanation:since mark obtain are distinct and integral.1st student scored 120,2nd 119,3rd 118...so on.obtain sequence is in A.P.so,sum=40*100.5=4020.sum=N/2(a+L),N=40 and a=120,substituting we get L=81,is the least score and next least will be 82 since series is in A.P.Hence avg=81+82/2=81.5
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