Question

The mass of 10^22 molecules of CuSO4•5 H2O is

Answer 1

Explanation:

=63.5+32+16×4+5 (1×2+16)

=63.5+32+64+5 (18)

=249.5

Answer 2

$\fbox{Answer = 4.14\:g}$

$Explanation :-$

Molar mass of $\[CuSO_{4}.5H_{2}O\]$ =

(63.5 + 32 + 64 + 90)g/mol = 249.5g mol

So, mass of 6.02 × 10²³ molecules of

$\[CuSO_{4}.5H_{2}O\]$ = 249.5 g.

Therefore, mass of 1 × 10²² molecules of

$\[CuSO_{4}.5H_{2}O\]$ =

249.5g × 1 × 10²²/6.02 × 10²³

$= \: \fbox{4.14\:g}$