Physics, asked by Priyaaaaaaa, 11 months ago

the mass of 2 kg is attached to a spring of force of force constant 200 N/m Find its time period

Answers

Answered by guduuu

so formula used is

F=k.x

2*10=200.x

x=0.1m

so time is

v2-u2=2as

v2=2*10*.1

v=√2

hope it helps

guduuu: yes after getting vel jaise Maine nikali hai. vel, acceleration, u=0 ki value put kar in. v=u+at main time aajayega

guduuu: Maine question half kiya kai

guduuu: hai*

guduuu: just put value in eq

guduuu: got it

Priyaaaaaaa: yeah thankyou so much

guduuu: agar samajh nai aaya to Dobara question post Karna I will answer but post bata kar Karna,, Taki koi aur ans na kare

guduuu: ohk gud sis

Priyaaaaaaa: yeah sure

guduuu: :-)

Answered by lidaralbany

Answer:

The time period will be 0.63 sec.

Explanation:

Given that,

Mass = 2 kg

Spring constant k = 200 N/m

The time period is defined as;

$T= 2\pi\sqrt{\dfrac{m}{k}}$

Here, T = time period

m = mass

k = spring constant

The time period will be

$T= 2\pi\sqrt{\dfrac{2}{200}}$

$T=0.63\ sec$

Hence, The time period will be 0.63 sec.

neha12380: Thx a lot I appreciate it

Previous Question

Next Question