Question

The mass of 50% solution of hcl required to react with 100g og caco3 would be

Answer 1

Answer:

·

molar mass of CaCO3=40+ 12+3*16=100g ... and as the solution has 50 % =0.5 of HCL, you need 73*2=146g. 4.7.

Answer 2

Answer:

The mass of 50% solution of $HCl$ required to react with $100g$ of $CaCO_{3}$ measured is $73g$.

Explanation:

Given,

The mass of $CaCO_{3}$ = $100g$

The mass of $HCl$ =?

As we know,

• The reaction of $HCl$ with$CaCO_{3}$ follows in the way given below:
• $2HCl + CaCO_{3} \rightarrow CaCl_{2} + CO +3H_{2}$

From this reaction, we can say that $2 moles$ of $HCl$ required to react with $1 mole$ of $CaCO_{3}$.

Now,

• The number of moles of $HCl$, n = $2 mol$
• Molar mass of $HCl$, M = $36.5g/L$

Therefore,

• The mass of $HCl$ = n × M = $2\times 36.5$ = $73g$.