The mass of a box measured by grocer's balance is 2.300 kg. Two gold pieces of masses 20.15 g and 20.17 g are added to the box. What is (a) the total mass of the box and (b) the difference in the masses of the pieces to correct significant figures.
Answers
Answered by
216
Hey friend,
# Answer-
a) Total mass of the box = 2.3 kg
b) Difference in masses = 0.02 g
# Given-
Mass of grocer’s box = 2.300 kg = 2.3 kg ...(2 significant figures)
Mass of 1st gold piece = 20.15 g = 0.02015 kg ...(4 significant figures)
Mass of 2nd gold piece = 20.17 g = 0.02017 kg ...(4 significant figures)
# Solutions-
After addition as well as substraction, mass should retain least significant figures i.e. here 2 and 4 respectively.
a) Total mass of the box
= 2.3 + 0.02015 + 0.02017
= 2.34032 kg
= 2.3 kg ...(2 significant figures)
b) Difference in masses
= 20.17 – 20.15
= 0.02 g ...(only 2 significant figures available)
Hope that helped you...
# Answer-
a) Total mass of the box = 2.3 kg
b) Difference in masses = 0.02 g
# Given-
Mass of grocer’s box = 2.300 kg = 2.3 kg ...(2 significant figures)
Mass of 1st gold piece = 20.15 g = 0.02015 kg ...(4 significant figures)
Mass of 2nd gold piece = 20.17 g = 0.02017 kg ...(4 significant figures)
# Solutions-
After addition as well as substraction, mass should retain least significant figures i.e. here 2 and 4 respectively.
a) Total mass of the box
= 2.3 + 0.02015 + 0.02017
= 2.34032 kg
= 2.3 kg ...(2 significant figures)
b) Difference in masses
= 20.17 – 20.15
= 0.02 g ...(only 2 significant figures available)
Hope that helped you...
Answered by
63
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Mass of grocer’s box = 2.300 kg
Mass of gold piece I = 20.15g = 0.02015 kg
Mass of gold piece II = 20.17 g = 0.02017 kg
Total mass of the box = 2.3 + 0.02015 + 0.02017 = 2.34032 kg
In addition, the final result should retain as many decimal places as there are in the number with the least decimal places. Hence, the total mass of the box is 2.3 kg. Difference in masses = 20.17 – 20.15 = 0.02 g
In subtraction, the final result should retain as many decimal places as there are in the number with the least decimal places.
I hope, this will help you
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