Question

The mass of a hypothetical substance that melts at 5°C is mx = 5.5 kg and its temperature is Tx = 5°C. This substance, as a solid, is added to mw = 19.5 kg of water at Ti = 65.0°C. The final temperature of the mixture became Tf = 260C.

Calculate the latent heat of fusion of this substance. Express your answer with one decimal place in units shown.

Useful data:
Assume that the specific heats are: cx = 0.980 kJ/kg°C and cwater = 4.186 kJ/kg°C.

Answer 1

Answer:

Latent heat of fusion for unknown substance is $5.6 \times 10^5 J/kg$

Explanation:

As we know that two substance are mixed together then after reaching the equilibrium the final temperature will be same for all

Here we know that heat given by one substance = heat absorbed by other substance

So we will have

$m_x L + m_x c_x (\Delta T_1) = m_w c_w\Delta T_2$

so here we will have

$5.5 L + (5.5 (980)(26 - 5)) = 19.5(4186)(65 - 26)$

$5.5 L = 3183453 - 113190$

$L = 5.6 \times 10^5 J/kg$

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Topic : Calorimetery

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