The mass of a planet is 6 times the mass of earth and its radius is three times that the Earth considering acceleration due to gravity on earth to be 9.8 M per second square calculate the value of g on the other planet
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Let mass of earth be Me and radius of earth be Re.
At earth's surface
g=GMe/Re^2
Let the mass of the planet be M' and radius be R'.
At planet's surface
g'=GM'/R'^2
according to given condition
M'=6Me,R'=3Re
g'=G6Me/(3Re)^2
g'=6GMe/9Re^2
g'=GMe/Re^2×6/9
we know GMe/Re^2=g
putting in the value of GMe/Re^2
g'=g×6/9
g'=9.8×6/9
g'=6.53m/s^2
hope it helps u.....
if any query plz let me know......
At earth's surface
g=GMe/Re^2
Let the mass of the planet be M' and radius be R'.
At planet's surface
g'=GM'/R'^2
according to given condition
M'=6Me,R'=3Re
g'=G6Me/(3Re)^2
g'=6GMe/9Re^2
g'=GMe/Re^2×6/9
we know GMe/Re^2=g
putting in the value of GMe/Re^2
g'=g×6/9
g'=9.8×6/9
g'=6.53m/s^2
hope it helps u.....
if any query plz let me know......
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