The mass of an electron is 9.1X10(-31) Kg .If its K.E is 6 X 10(-30) J . Calculate its wavelength .
Answers
Answer:
2.1×10^(11)m or 210 nanometers.
Explanation:
Mass of electron = 9.1 ×10^(-31) kg
Kinetic energy of electron = 6 ×10^(-30) J
》 K.E. = 1/2 mv^2
1/2 mv^2 = 6 ×10^(-30)
mv^2 = 6 ×2 ×10^(-30)
v^2 = 12 ×10^(-30)
v = _/12×10^(-30)
v = 3.464 × 10^(-15) m/s
》De broglie's matter wave hypothesis equation
wavelength = h/p or h/mv
here h is planck's constant which is 6.626 ×10^(-34)Js
and p is momentum of particle.
wavelength of given electron = h/mv
= 6.626 ×10^(-34) / 9.1×10^(-31)×3.464×10^(-15)
= 6.626 ×10^(-34+31+15) / 9.1×3.464
= 6.626 / 31.52 × 10^(12)
= 0.21 × 10^(12)
= 2.1 ×(11) m
= 210 nm.