The mass of an iron cube having an edge length 1.8cm is 70g. Find its density.
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Mass = 70 g
Edge of the cube= 1.8 cm
Volume of the cube = s^3= (1.8)^3
=5.832 cm^3
Density = mass/ volume
= 70/5.832
= 12.002 g/cm^3
Edge of the cube= 1.8 cm
Volume of the cube = s^3= (1.8)^3
=5.832 cm^3
Density = mass/ volume
= 70/5.832
= 12.002 g/cm^3
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