Math, asked by atharvshukla27, 29 days ago

The mass of and empty density bottle is 35 g, it is 75 g when completely filled with water and 67 g when filled with methanol. Calculate the relative density of methanol

Answers

Answered by panchalshyama59
0

Step-by-step explanation:

Mass of empty density bottle, M1 = 30 grams

MAss of bottle and water, M2 = 75 grams

Mass of liquid and liquid x, M3 = 65 grams

Mass of water = M2 – M1 = 45 grams

a) Volume of density bottle = Mass of water = 45 grams

b) Density of liquid x, D = mass of liquid/mass of water = 35/45

Mass of iquid = M3 – M1 = 65 – 30 = 35 grams

D = Mass of liquid/mass of water = 35/45 = 0.77 grams/cm3

c) Mass of water in the density bottle = 75 – 30 = 45 grams

Therefore, the volume of water in density bottle = 45 cc

Mass of the liquid whose volume is equal to the density bottle = 65 – 30 = 35 grams

Therefore, relative density of the liquid = mass of 45 cc of liquid/mass of 45 cc of water = 35/45 = 7/9 = 0.77

Answered by Anonymous
0

Answer:

Step-by-step explanation:

Mass of empty density bottle, M1 = 35 grams

Mass of bottle and water, M2 = 75 grams

Mass of Methanol, M3 = 67 grams

Mass of water = M2 – M1 = 75-35 grams=40grams

a) Volume of density bottle = Mass of water = 40 grams

Mass of iquid = M3 – M1 = 67 – 35 = 32 grams

b) Density of methanol , D = mass of liquid/mass of water = 32/40

D = Mass of liquid/mass of water = 32/45 = 0.71 grams

c) Mass of water in the density bottle = 75 – 35 = 40 grams

Therefore, the volume of water in density bottle = 40 grams

Mass of the liquid whose volume is equal to the density bottle = 67 – 35 = 32 grams

Therefore, relative density of methanol = = 32/40 = 0.8

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