Question

The mass of calcium chloride formed when 2.5g calcium carbonate are dissolved in excess of HCL acid is?

Answer 1

Answer:

5.55g

Explanation:

2.5/100=0.025mol caco3 reacts with 2*0.025=0.05mol hcl

here HCL is limiting reagent

therefore, moles of cacl2 is also 0.05

mass=0.05*111=5.55g

Answer 2

Answer:

5.55g

Explanation:

2.5/100=0.025mol caco3 reacts with 2*0.025=0.05mol hcl

here HCL is limiting reagent

therefore, moles of cacl2 is also 0.05

mass=0.05*111=5.55g