Question

A bag contains 5 black and 6 white balls.If two balls are drawn togethwr at random then the probablity that these being of different colours

Answer 1

Answer:

Step-by-step explanation:

We have 5 black & 6 white balls.

So total = 5+6= 11

So 2 balls can be drawn from 11 in 11c2 ways i.e 55 ways.

Now it is required to calculate the favourable cases. Two balls of different colours mean one black & another white.

1 black can be drawn from 5 in 5 ways & 1 white can be drawn from 6 in 6 ways.

Answer 2

Answer:

6/11

Step-by-step explanation:

We have 5 black & 6 white balls.

So total = 5+6= 11

So 2 balls can be drawn from 11 in 11c2 ways i.e 55 ways.

Now it is required to calculate the favourable cases. Two balls of different colours mean one black & another white.

1 black can be drawn from 5 in 5 ways & 1 white can be drawn from 6 in 6 ways.

So one black & one white in 5*6= 30 ways

So required probability = 30/55= 6/11