The mass of cyclist together with bike is 90kg. Calculate the increase in kinetic energy if the speed increases from 6km/hr to 12km/hr.
Answers
Answered by
150
initial speed = 6km/hr = 5/3 m/s
final speed = 12km/hr = 10/3 m/s
∆KE = 1/2 m(v² - u²)
= 1/2 x 90(100/9 - 25/9)
= 375 J
Here ∆KE = Change in kinetic energy
m is mass
v is final velocity
u is initial velocity
final speed = 12km/hr = 10/3 m/s
∆KE = 1/2 m(v² - u²)
= 1/2 x 90(100/9 - 25/9)
= 375 J
Here ∆KE = Change in kinetic energy
m is mass
v is final velocity
u is initial velocity
Similar questions
Science,
8 months ago
Math,
1 year ago
English,
1 year ago
Biology,
1 year ago
Social Sciences,
1 year ago