the mass of cyclist together with the bike is 90 kg calculate the increasing kinetic energy pte speed increased from 6 km per hour to 12 km per hour
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Total mass of the system (cyclist and bike), M=mc+mb=90 kg
Initial velocity of the system, u=6.0 km/h=1.666 m/sec
Final velocity of the system, ν=12 km/h=3.333 m/sec
From work-energy theorem, we have:
Increase in K.E.=12Mν2−12mu2=1290×(3.333)2−12×90×(1.66)2=499.4−124.6=374.8=375 J
Initial velocity of the system, u=6.0 km/h=1.666 m/sec
Final velocity of the system, ν=12 km/h=3.333 m/sec
From work-energy theorem, we have:
Increase in K.E.=12Mν2−12mu2=1290×(3.333)2−12×90×(1.66)2=499.4−124.6=374.8=375 J
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Answer:
The mass of the cyclist together with the bike is 90 kg. The increasing kinetic energy when speed increased from 6 km per hour to 12 km per hour is 375 J.
Explanation:
Given,
The total mass (m) = 90 kg
Initial speed = 6 km/hr =
Final speed = 12 km/hr =
We have the expression for Kinetic energy (K.E) as,
So the change in K.E will be,
=
= J
≈ 375 J
Ans:
The Increase in kinetic energy = 375 J
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