the mass of half mole of electron is about
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Answer:
1 mole of electron contains 6.022 × 10²³ electrons.
So, 1/2 mole of electron will contain 3.011 × 10²³ electrons.
Mass of one electron is = 9.109 × 10^-28 g
So, mass of 3.011 × 10-²³ electrons will be
\begin{lgathered}= 3.011 \times {10}^{ 23} \times 9.101 \times {10}^{ - 28} \: g \\ \\ = 27.4 \times {10}^{ - 5} \: g \\ \\ = 27.4 \times {10}^{ - 5} \times {10}^{3} \: mg \\ \\ = 27.4 \times {10}^{ - 2} \: mg \\ \\ = 0.274 \: mg\end{lgathered}=3.011×1023×9.101×10−28g=27.4×10−5g=27.4×10−5×103mg=27.4×10−2mg=0.274mg
Therefore mass of 1/2 mole of electron is = 0.274 mg
Hope this helps...
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