Chemistry, asked by shivammunde78, 11 months ago

The mass of Mg3N2 produced, if 48 g of Mg metal reacted with 34 g of NH3 gas is
(Mg = 24, N=14, H=1)

3Mg + 2NH2 → Mg3N2 + 3H2

Answers

Answered by himanshujain918

0

Answer:

0.667

Explanation:

48 gm MG = 2mol

34 gm nh3= 2mol

in rxn N(mg3n2)=mol of mg/ schtochiyoimetric cofficent of mg

=2/3

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