Question

the mass of Sulphur dioxide that will contain 6.022 into 10 raise to 22 molecules is..
a. 0.64g
b. 32.0g
c. 6.4g
d. 64.0g

please give me the explanation of the question..​

Answer 1

Answer:

We know that,

No.of moles= No.of molecules/ Avogadro's No.

No.of moles= 6.022×10^22/6.022×10^23= 0.1 moles.

1 mole of SO2 contains 64gm by mass.

So 0.1 moles of SO2 contains 64×0.1= 6.4 gm.

So correct option is (c).

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Answer 2

Answer = 6.4g (c)

Explanation:-

Sulphur dioxide is commonly known as NO2

The molar mass of NO2 = N + (2 x O)

                                        = 32 + (2 x 16)

                                        = 32 + 32

                                        = 64 g/moles

Given mass (m) = no of particles(No)    x    Molar mass(M)

                              Avogadro's constant

                          = 6.022 x 10^22   x     64  

                                6.022 x 10^23

                          =  64  x         1    

                                              10

                          = 6.4 g

So, 6.022 x 10^22 molecules of sulphur dioxide will contain 6.4g of mass

HOPE IT HELPS.