Question

the mass of the ship is 2*10^7 kg. on applying a force of 25*10^5 N, it is displaced by 25 m After displacement the speed aquired by the ship will be​

Answer 1

Answer:

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Answer 2

Answer:

v=2.5 m/s

Explanation:

Given that

Mass $m= 2 \times 10^7\ kg$

Force

$F=25\times 10^5\ N$

From second law of Newton's

F = m a

F=Net force

m = Mass

a =Acceleration

$25\times 10^5 = 2 \times 10^7\times a$

 a= 0.125 m/s²

Let initial speed of ship is zero , u = 0 m/s

The final speed of ship after 25 m is v m/s

We know that

v²=u² + 2 a s

Here s= 25 m

a = 0.125 m/s²

u o m/s

v²= 2 x 0.125 x 25

v=2.5 m/s