the mass of thousand kgs having a speed of 10 M per second is brought to rest over a distance of 100 M find the retardation
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V²=u²+2as
0=10*10+2a(100)
0=100+200a
-100=200a
a=-100÷200
a=-2m/s²
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0=10*10+2a(100)
0=100+200a
-100=200a
a=-100÷200
a=-2m/s²
Hope it helps if it does plz follow me so that i can take up more of ur doubts
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plz follow me
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